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The points of intersection of three lines, $2X + 3Y - 5 = 0, 5X - 7Y + 2 = 0$, and $9X-5Y-4 =0$:

  1. form a triangle.
  2. are on lines perpendicular to each other.
  3. are on lines parallel to each other.
  4. are coincident.
asked in Quantitative Aptitude by (4.8k points) 38 105 176
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2 Answers

+2 votes

IF THREE LINES ARE  COINCIDENT THEN AREA OF TRIANGLE   MUST BE  ZERO(0).

answered by (494 points) 3 15
+1 vote

SOLVE  OF THE THESE THREE LINES AND GET THE INTERSECTION POINT.

 

 

answered by (494 points) 3 15
Good explanation sir

thank you

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