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P, Q and R are three consecutive odd numbers in ascending order. If the value of three times P is three less than two times R, find the value of R.

1. $5$
2. $7$
3. $9$
4. $11$

Let,

P =  x - 2

Q =  x

R = x + 2

given that,

3P = 2R - 3

on substituting the values of P  and R,

we get,

3 * (  x- 2 ) = 2 * ( x + 2 ) - 3

3x - 6 = 2x + 4 - 3

3x - 2x = 4 - 3 + 6

x = 7

P = 7 - 2 = 5

Q = 7

R = 9

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