P, Q and R are three consecutive odd numbers in ascending order. If the value of three times P is three less than two times R, find the value of R.
Let,
P = x - 2
Q = x
R = x + 2
given that,
3P = 2R - 3
on substituting the values of P and R,
we get,
3 * ( x- 2 ) = 2 * ( x + 2 ) - 3
3x - 6 = 2x + 4 - 3
3x - 2x = 4 - 3 + 6
x = 7
P = 7 - 2 = 5
Q = 7
R = 9