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AB is the diameter of the given circle, while points C and D lie on the circumference as shown. If AB is $15$ cm, AC is $12$ cm and BD is $9$ cm, find the area of the quadrilateral ACBD.

1. $54 \pi$
2. $216\pi$​​​​​​​
3. $162\pi$​​​​​​​
4. None of these

Angle C and D will be right angles

BC will be 9 cm (Applying Pythagoras theorem)

AD will be 12 cm (Applying Pythagoras theorem)

Area of the quadrilateral = Area of triangle ABC + Area of triangle ABD

= 54 + 54 = 108 cm square
326 points

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