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$2^{1}=2 \ ; \ 2^{2} = 4 \ ; \ 2^{3}=8 \ ;\ 2^{4}=16$

$2^{5}=32 \ ; \ 2^{6} = 64 \ ; \ 2^{7}=128 \ ;\ 2^{8}=256$

From above it is clear that the Cyclicity of 2 is 4.
 

$2^{51}=2^{48}\times 2^{3}$

Unit place of 48=6

Unit place of 49=2

Unit place of 50=4

Hence, unit place of $2^{51}=8$

 

Hence,Option(B)8.
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