A cow is tethered at A by a rope. Neither the rope nor the cow is allowed to enter the triangle $ABC$.
$m\angle A=30^{\circ}$
$1(AB)=1(AC)=10m.$
$1(BC)=6m$
What is the area that can be grazed by the cow if the length of the rope is 12 m?
- $133 1/6$ p sq.m
- $121$ p sq.m
- $132$ p sq.m
- $176/3$ p sq.m