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$(BE)^{2} = MPB$, where $B, E, M$ & $P$ are distinct integers, then $M$?

1. $2$
2. $3$
3. $9$
4. None of these

+1 vote

There is only one possibility.

$19^{2}=361$

Here B=1

E=9

M=3

P=6

Here all numbers are distinct.

Hence,Option(B) 3 should be the correct choice.