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The number that least fits this set: (324, 441, 97 and 64) is ________.
(A) 324 (B) 441 (C) 97 (D) 64

97 - all others are perfect squares while 97 is a prime number.

$18^2 = 324$

$21^2 = 441$

$8^2 = 64$
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Last yr iisc banglore has given answer C and D both as correct.. can you please tell me how it can be D 64 ?
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May be sum of the digits not being a perfect square.
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thanks buddy....this question was hitting my head from last 1 yr.... bythe way nice catch...

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