1 votes 1 votes The square of two digit number(ab) divided by half of itself resultant added by 18 then divided by 2 then we get reverse of original number(ba). how many combination of ab exist 9 8 7 6 Quantitative Aptitude difficult quantitative-aptitude + – malti007 asked Feb 21, 2017 • recategorized Aug 10, 2017 by go_editor malti007 26 points 1.3k views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes $\frac{(ab)^{2}}{\frac{1}{2}* ab} =2* ab$ 2*ab+18 $\frac{2*ab+18}{2}$ ab+9 =ba ba-ab=9 their are 8 possibilities 21-12 =9 32-23=9 43-34=9 54-45=9 65-56=9 76-67=9 87-78=9 98-89=9 shivanisrivarshini answered Mar 1, 2017 • edited Mar 1, 2017 by shivanisrivarshini shivanisrivarshini 1.9k points comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes $(2(10a+b)^2/(10a+b) + 18) / 2 = 10b+a \Rightarrow 10a+b+9 = 10b +a \Rightarrow 9a-9b+9 = 0 \Rightarrow a - b + 1 = 0$ Therefore the possible values of a and b are: a b 1 0 2 1 3 2 . . . 9 8 Hence, possible combinations of a and b are 9. Ravi R Y answered Jun 14, 2019 Ravi R Y 94 points comment Share See all 0 reply Please log in or register to add a comment.