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In the given figure, $∠BAC = 120º$  and $AD$ is the bisector of $∠BAC$. If $\frac{(AD)(AB)}{BD} = \frac{AE}{EC}( AE + EC )$ and $∠EDC = ∠ECD$, what is the ratio of $∠B$ and $∠C$?

  1. 1 : 1
  2. 1 : 2
  3. 2 : 3
  4. 5 : 6
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where is the figure. plz upload one
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is ans 1:1

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