In the given figure, ∠BAC = 120° and AD is the bisector of ∠BAC.

Question

In the given figure, $∠BAC = 120º$  and $AD$ is the bisector of $∠BAC$. If $\frac{(AD)(AB)}{BD} = \frac{AE}{EC}( AE + EC )$ and $∠EDC = ∠ECD$, what is the ratio of $∠B$ and $∠C$?

1. 1 : 1
2. 1 : 2
3. 2 : 3
4. 5 : 6

Comments

where is the figure. plz upload one

Answer 1

is ans 1:1

?

Answer 2

1.1:1