Here the letters decrease by 1; the numbers are multiplied by 2.
$(F-1)(2\times2)=E4$
$(E-1)(4\times2)=D8$
$(D-1)(8\times2)=C16$
$(C-1)(16\times2)=B32$
Alphabets are written in the reverse pattern, the number is in $2^n,n=1,2,3,4….$ that is;
So the missing term is $E4.$