1 votes 1 votes poomittal asked Nov 9, 2016 poomittal 26 points 1.1k views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Let the original price be $x$. Nikita's selling price = Nisha's buying price = 0.72x Nisha's selling price = Kavya's buying price = (0.72x + 3360) * 1.125 = 94500. So, $x = \left(\frac{94500}{1.125} - 3360\right)/0.72$ $= 112,000$ Arjun answered Nov 10, 2016 • selected Dec 17, 2016 by Leen Sharma Arjun 8.6k points comment Share See all 2 Comments See all 2 2 Comments reply Maqbool 10 points commented Dec 12, 2016 reply Share Can any explain the solution above ? 0 votes 0 votes Leen Sharma 11.5k points commented Dec 17, 2016 reply Share Let the original price be =x. Nikita's selling price = Nisha's buying price = $\frac{(100-28) \times x}{100}=\frac{78x}{100}=0.72x$ Nisha's selling price = Kavya's buying price = 94500. NIsha sold car to kavya at 94500 after repairing and car sold at $\frac{25}{2}=12.5$% profit. Nisha selling price=$\frac{{}( Nisha's \\\ buying\\\ price + repairing\\\ cost ) \times rate} {100}$ $\frac{(0.72x+ 3360 ) \times(100+12.5)} {100}=94500$ $=\frac{(0.72x+ 3360 ) \times(112.5)} {100}=94500$ $=(0.72x+ 3360 )=\frac{94500\times100}{112.5}$ $x=\frac{\frac{94500}{1.125}-3360}{0.72}$ $x=112000$ 0 votes 0 votes Please log in or register to add a comment.