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Nikita sold a car to nisha at 28%loss and nisha sold the same car to kavya at 94500 afte having a repair of 3360 at 25/2% profit what is the original price of car?
poomittal
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Let the original price be $x$.
Nikita's selling price = Nisha's buying price = 0.72x
Nisha's selling price = Kavya's buying price = (0.72x + 3360) * 1.125 = 94500.
So, $x = \left(\frac{94500}{1.125} - 3360\right)/0.72$
$= 112,000$
Arjun
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Nov 11, 2016
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Dec 17, 2016
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Leen Sharma
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Can any explain the solution above ?
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Leen Sharma
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Let the original price be =x.
Nikita's selling price = Nisha's buying price = $\frac{(100-28) \times x}{100}=\frac{78x}{100}=0.72x$
Nisha's selling price = Kavya's buying price = 94500.
NIsha sold car to kavya at 94500 after repairing and car sold at $\frac{25}{2}=12.5$% profit.
Nisha selling price=$\frac{{}( Nisha's \\\ buying\\\ price + repairing\\\ cost ) \times rate} {100}$
$\frac{(0.72x+ 3360 ) \times(100+12.5)} {100}=94500$
$=\frac{(0.72x+ 3360 ) \times(112.5)} {100}=94500$
$=(0.72x+ 3360 )=\frac{94500\times100}{112.5}$
$x=\frac{\frac{94500}{1.125}-3360}{0.72}$
$x=112000$
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