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In a sequence of 12 consecutive odd numbers, the sum of first 5 numbers is 425.What is the sum of last 5 numbers in the sequence?

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Sum of first 5 numbers are 425

Middle of the numbers are 425/5=85

So, first 5 numbers are 81,83,85,87,89

Last 5 numbers of this sequence is 95,97,99,101,103

Summation of these are 495
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