Possible combination to get $6$ as sum $= (2,4) (4,2) (3,3) (5,1) (1,5)$
Possible combination to get $9$ as sum $= (4,5) (5,4) (6,3) (3,6)$
The probability that the total is $6 =\frac{5}{36}=0.138$
The probability that the total is $9 =\frac{4}{36}=0.111$
Here,
The probability that the total is $6 >$ The probability that the total is $9$
$0.138 > 0.111$
Hence, the probability that the total is 6 is greater than the probability that the total is $9.$
Correct Answer: C