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**Answer the question based on the following information.**

A road network (shown in the figure below) connects cities A, B, C and D. All road segments are straight lines. D is the mid-point on the road connecting A and C. Roads AB and BC are at right angles to each other with BC shorter than AB. The segment AB is $\text{100 km}$ long.

Ms X and Mr Y leave A at $\text{8.00 a.m.,}$ take different routes to city C and reach at the same time. X takes the highway from A to B to C and travels at an average speed of $\text{61.875 kmph.}$ Y takes the direct route AC and travels at $\text{45 kmph}$ on segment AD. Y’s speed on segment DC is $\text{55 kmph.}$

The total distance travelled by Y during the journey is approximately

- $\text{105 km}$
- $\text{150 km}$
- $\text{130 km}$
- Cannot be determined

4 votes

**Kindly have a look on its first part . http://aptitude.gateoverflow.in/2323/cat1999-105
here i calculated the value of AD=BD=52.5 km
so the distance travelled by Y is AC =(AD+DC)= 52.5+52.5 =105 km
so option (A) is correct . **