The closest pair of points among the pairs (A, C), (A, D), (A, E), (F, C), (F, D), (F, E), (B, C), (B, D), (B, E) are**10 3 cm **apart.

**its 10√ 3 cm ** apart!!

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**Answer the question based on the following information.**

A rectangle PRSU, is divided into two smaller rectangles PQTU, and QRST by the line TQ. PQ $= 10$ cm. QR $= 5$ cm and RS $= 10$ cm. Points A, B, F are within rectangle PQTU, and points C, D, E are within the rectangle QRST. The closest pair of points among the pairs (A, C), (A, D), (A, E), (F, C), (F, D), (F, E), (B, C), (B, D), (B, E) are10 3 cm apart.

AB > AF > BF ; CD > DE > CE ; and BF $= 6 \sqrt{5}$ cm. Which is the closest pair of points among all the six given points?

- B, F
- C, D
- A, B
- None of these