CAT 1999 | Question: 64

Question

If $|r − 6| = 11$ and $|2q − 12| = 8$, what is the minimum possible value of $\frac{q}{r}$?

• A. $- \frac{2}{5}$
• B. $\frac{2}{17}$
• C. $\frac{10}{17}$
• D. None of these

Answer 1

|r − 6 |= 11  

 r − 6 = 11, r = 17

or –(r – 6) = 11, r = –5

| 2q – 12 | =8 

2q –12 = 8 , q = 10

or 2q – 12 = –8 , q =2

Hence, minimum value of $\frac{10}{-5}= -2$

 

Hence, Option(D)None of these is the Answer.