382 views

If $|r − 6| = 11$ and $|2q − 12| = 8$, what is the minimum possible value of $\frac{q}{r}$?

1. $- \frac{2}{5}$
2. $\frac{2}{17}$
3. $\frac{10}{17}$
4. None of these

|r − 6 |= 11

r − 6 = 11, r = 17

or –(r – 6) = 11, r = –5

| 2q – 12 | =8

2q –12 = 8 , q = 10

or 2q – 12 = –8 , q =2

Hence, minimum value of $\frac{10}{-5}= -2$

Hence, Option(D)None of these is the Answer.

11.1k points

1