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1 vote

A student walks to the bus stop to catch a bus to the university. He then walks from the bus stop at the university to the students union arriving there at $8:35 \; \text{am.}$

How far does the student walk in total?

- $1 \; \text{Km}$
- $2 \; \text{Km}$
- $3 \; \text{Km}$
- $4 \; \text{Km}$
- $5 \; \text{Km}$

How far is he from university student's union at $8:20 \; \text{am}?$

- $1 \; \text{Km}$
- $2 \; \text{Km}$
- $3 \; \text{Km}$
- $4 \; \text{Km}$
- $5 \; \text{Km}$

What is the average speed of the bus?

- $14 \; \text{Kmph}$
- $24 \; \text{Kmph}$
- $40 \; \text{Kmph}$
- $48 \; \text{Kmph}$

2 votes

1. How far does student walk:-** option 2**

sol; 1 km before bus stop and 1 km after bus stop to university= **2 km**

2. How far is he from university student's union at 8.20 am? **option 3**

sol: at 8:20 student has covered 3 km and university is 6 km far from start point .So 6-3= **3 km**

3. What is the average speed of the bus? **option 2**

sol: bus starts at 8:15 to 8:25 (10 minutes) and covers 4 km

average speed = distance/time= 4km/10 min= **24 KMPH**