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CAT 2003 | Question: 2-94

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Any number that gives a remainder of 3 when divided by 7 will be of the form 7n + 3.
Since we only need two-digit numbers, n will range

$$\sum_{n=1}^{13} 7n+3 $$

= 13 × 3 + 7(1 + 2 + … + 13)
= 39 + 637 = 676

Hence, option (2).676

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