CAT 2003 | Question: 2-75

Question

Using only $2, 5, 10, 25$ and $50$ paise coins, what will be the minimum number of coins required to pay exactly $78$ paise, $69$ paise and Rs  $1.01$ to three different persons?

• A. $19$
• B. $20$
• C. $17$
• D. $18$

Answer 1

 To pay 78 paise using minimum number of coins:
78 = 1(50) + 2(10) + 4(2) => 7 coins required

To pay 69 paise using minimum number of coins:
69 = 1(50) + 1(10) + 1(5) + 2(2) => 5 coins required

To pay 101 paise using minimum number of coins:
101 = 1(50) + 1(25) + 2(10) + 3(2) =>7 coins required

Minimum coins required :- 7 + 5 + 7 = 19 coins

Hence,(A) 19 is the Answer.