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If n is such that $36 \leq n \leq 72$ then $x = \frac{n^2 + 2 \sqrt{n}(n+4) +16}{n+4\sqrt{n}+4}$ satisfies

  1. $20 < x < 54$
  2. $23 < x < 58$
  3. $25 < x < 64$
  4. $28 < x < 60$
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Answer C)

put 36 and 72 in the equation to get range
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