0 votes 0 votes If $a, a + 2$ and $a + 4$ are prime numbers, then the number of possible solutions for $a$ is: one two three more than three Quantitative Aptitude cat2003-2 quantitative-aptitude algebra + – go_editor asked May 4, 2016 • edited Mar 31, 2022 by Lakshman Bhaiya go_editor 13.9k points 471 views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes There is only one Triplet of prime numbers where difference between any two prime numbers is 2 that is 3,5 and 7. So N=3 is the only the solution. Hence,Option(A)One is the Answer. srestha answered May 4, 2016 • selected May 16, 2016 by Leen Sharma srestha 5.2k points comment Share See all 0 reply Please log in or register to add a comment.