CAT 2003 | Question: 2-54

Question

If $a, a + 2$ and $a + 4$ are prime numbers, then the number of possible solutions for $a$ is:

• A. one
• B. two
• C. three
• D. more than three 

Answer 1

There is only one Triplet of prime numbers where difference between any two prime numbers is 2 that is 3,5 and 7.

So N=3 is the only the solution.

Hence,Option(A)One is the Answer.