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If $a, a + 2$ and $a + 4$ are prime numbers, then the number of possible solutions for $a$ is:

1. one
2. two
3. three
4. more than three

There is only one Triplet of prime numbers where difference between any two prime numbers is 2 that is 3,5 and 7.

So N=3 is the only the solution.

Hence,Option(A)One is the Answer.

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