2 votes 2 votes Let $n$ be the number of different $5$ digit numbers, divisible by $4$ with the digits $1, 2, 3, 4, 5$ and $6,$ no digit being repeated in the numbers. What is the value of $n?$ $144$ $168$ $192$ None of these Quantitative Aptitude cat2001 quantitative-aptitude number-systems + – go_editor asked Apr 1, 2016 • edited Jun 5, 2023 by Lakshman Bhaiya go_editor 13.9k points 680 views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Answer will be 192 last two digits could be 12,32,52,24,64,16,36,56 Now numbers are 8 * 4C3 * 3! =192 srestha answered Apr 1, 2016 • selected Apr 3, 2016 by Arjun srestha 5.2k points comment Share See all 0 reply Please log in or register to add a comment.