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Let $n$ be the number of different $5$ digit numbers, divisible by $4$ with the digits $1, 2, 3, 4, 5$ and $6,$ no digit being repeated in the numbers. What is the value of $n?$

1. $144$
2. $168$
3. $192$
4. None of these

last two digits could be 12,32,52,24,64,16,36,56

Now numbers are 8 * 4C3 * 3! =192
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