CAT 2001 | Question: 36

go_editor asked Mar 31, 2016 • edited Apr 10, 2022 by Lakshman Bhaiya

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Three runners A, B and C run a race, with runner A finishing $12$ metres ahead of runner B and $18$ metres ahead of runner C, while runner B finishes $8$ metres ahead of runner C. Each runner travels the entire distance at a constant speed. What was the length of the race?

$36$ meters
$48$ meters
$60$ meters
$72$ meters

Quantitative Aptitude
cat2001
quantitative-aptitude
speed-distance-time

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go_editor asked Mar 31, 2016 • edited Apr 10, 2022 by Lakshman Bhaiya

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Answer 48 meter

When B is 12 meters back from the finishing line A ends the race.

B went last 12 meters, when he gained 2 meters more from C (from 6 meters ahead to C when A finishes to 8 meters ahead to C when B finishes)

At the end of race B is 8 meters ahead from C

For 2 meter ahead from C, B needed to cover total 12 meters

" 8 " " " C , B " " " " 12/2 *8 = 48 meters

srestha answered Apr 1, 2016 • selected Apr 3, 2016 by Arjun

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Arjun

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That's an awesome explanation (y)

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