1 votes 1 votes The owner of an art shop conducts his business in the following manner: Every once in a while he raises his prices by $\text{X}\%$, then a while later he reduces all the new prices by $\text{X}\%.$ After one such up-down cycle, the price of a painting decreased by Rs. $441.$ After a second up-down cycle the painting was sold for Rs. $1,944.81.$ What was the original price of the painting? Rs $2,756.25$ Rs $2,256.25$ Rs $2,500$ Rs $2,000$ Quantitative Aptitude cat2001 quantitative-aptitude cost-price-selling-price + – go_editor asked Mar 31, 2016 • edited Apr 10, 2022 by Lakshman Bhaiya go_editor 13.8k points 7.1k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Let the original price be P and x%=a P-P*(1+a)*(1-a)=441 P*a^2=441 Again, P*((1+a)*(1-a))^2=1944.81 P*(1-a^2)^2=1944.81 Dividing, (1-a^2)^2/a^2=1944.81/441=4.41 (1-a^2)/a=2.1 a=2/5 P*(2/5)^2=441 P=441*25/4=2756.25 Jit Saha answered Jul 31, 2017 Jit Saha 18 points comment Share See all 0 reply Please log in or register to add a comment.