1 votes 1 votes In $\triangle \text{DEF}$ shown below, points $\text{A, B,}$ and $\text{C}$ are taken on $\text{DE, DF}$ and $\text{EF}$ respectively such that $\text{EC = AC}$ and $\text{CF = BC}.$ If $\measuredangle \text{D} = 40^{\circ}$, then what is $\measuredangle \text{ACB}$ in degrees? $140$ $70$ $100$ None of these Quantitative Aptitude cat2001 quantitative-aptitude geometry + – go_editor asked Mar 31, 2016 edited Sep 9, 2023 by makhdoom ghaya go_editor 13.8k points 3.6k views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes So ans is 3. 100 Shamik Kundu answered Mar 31, 2016 selected Mar 31, 2016 by Arjun Shamik Kundu 118 points comment Share See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Ans: (3). 100 solution: Let the angle E be x in triangle(AEC),then angle AEB= 180-2*x. Then in triangle DEF, angle F=180-(40+x). Now in triangleBCF, angle BCF=2*x-100. NOW,angle ACB= 180-(180-2*x+2*x-100)=100 nityanand32 answered Mar 31, 2016 nityanand32 40 points comment Share See all 0 reply Please log in or register to add a comment.