0 votes 0 votes If $a, b, c$ and $d$ are four positive real numbers such that $abcd = 1,$ what is the minimum value of $(1 + a)(1 + b)(1 + c)(1 + d)?$ $4$ $1$ $16$ $18$ Quantitative Aptitude cat2001 quantitative-aptitude algebra + – go_editor asked Mar 31, 2016 • edited Apr 10, 2022 by Lakshman Bhaiya go_editor 13.9k points 676 views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Using A.M>=GM GIVEN abcd=1, (a+b+c+d)/4=(abcd)^¼ hence a+b+c+d=4. using this find (1+a)(1+b)(1+c)(1+d) ,which is 16 Akhilmaddili12311 answered Nov 21, 2023 Akhilmaddili12311 60 points comment Share See all 0 reply Please log in or register to add a comment.