Register

CAT 2000 | Question: 101

• edited by
395 views

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
0 answers
3
go_editor asked Mar 29, 2016
404 views
CAT 2000 | Question: 102
In the figure above, $\text{AB = BC = CD = DE = EF = FG = GA}.$ Then $\measuredangle \text{DAE}$ is approximately $15^{\circ}$ $20^{\circ}$ $30^{\circ}$ $25^{\circ}$
In the figure above, $\text{AB = BC = CD = DE = EF = FG = GA}.$ Then $\measuredangle \text{DAE}$ is approximately$15^{\circ}$ $20^{\circ}$$30^{\circ}$$25^{\circ}$
0 votes
0 votes
1 answer
5
go_editor asked Mar 29, 2016
1,294 views
CAT 2000 | Question: 96
$\text{ABCD}$ is a rhombus with the diagonals $\text{AC}$ and $\text{BD}$ intersecting at the origin on the $x-y$ plane. The equation of the straight line $\text{AD}$ is $x + y = 1.$ What is the equation of $\text{BC}?$ $x + y = –1$ $x – y = –1$ $x + y = 1$ None of the above
$\text{ABCD}$ is a rhombus with the diagonals $\text{AC}$ and $\text{BD}$ intersecting at the origin on the $x-y$ plane. The equation of the straight line $\text{AD}$ is ...
Link Copied!