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CAT 2000 | Question: 59

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go_editor asked Mar 28, 2016
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CAT 2000 | Question: 58
If $a_1 = 1$ and $a_{n+1} = 2a_{n + 5}, n = 1, 2, \dots ,$ then $a_{100}$ is equal to $(5 × 2^99 – 6)$ $(5 × 2^99 + 6)$ $(6 × 2^99 + 5)$ $(6 × 2^99 – 5)$
If $a_1 = 1$ and $a_{n+1} = 2a_{n + 5}, n = 1, 2, \dots ,$ then $a_{100}$ is equal to$(5 × 2^99 – 6)$$(5 × 2^99 + 6)$$(6 × 2^99 + 5)$$(6 × 2^99 – 5)$
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