Register

CAT 2000 | Question: 57

• edited by
529 views
0 votes
0 votes

$\begin{array}{|c|c|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 & 6 \\\hline y & 4 & 8 & 14 & 22 & 32 & 44 \\\hline \end{array}$

In the above table, for suitably chosen constants $a, b$ and $c,$ which one of the following best describes the relation between $y$ and $x?$

  1. $y = a + bx$
  2. $y = a + bx + cx^2$
  3. $y = e^{a + bx}$
  4. None of the above
• edited by
User Avatar

1 Answer

0 votes
0 votes
Answer is B
Take a=2, b=1, c=1 then checking different values
F(1) = 2+(1*1)+(1*1)=4
F(2) = 2+(1*2)+(1*4)= 8

In this way all values are satisfied...
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
0 answers
3
go_editor asked Mar 28, 2016
390 views
CAT 2000 | Question: 70
Each of the numbers $x_1, x_2,\dots, x_n, n > 4,$ is equal to $1$ or $–1.$ Suppose, $x_1x_2x_3x_4 + x_2x_3x_4x_5 + x_3x_4x_5x_6 + \dots + x_{n–3}x_{n–2}x_{n–1}x_n + x_{n–2}x_{n–1}x_nx_1+ x_{n–1}x_nx_1x_2 + x_nx_1x_2x_3= 0$, then, $n$ is even. $n$ is odd. $n$ is an odd multiple of $3.$ $n$ is prime
Each of the numbers $x_1, x_2,\dots, x_n, n 4,$ is equal to $1$ or $–1.$ Suppose, $x_1x_2x_3x_4 + x_2x_3x_4x_5 + x_3x_4x_5x_6 + \dots + x_{n–3}x_{n–2}x_{n–1}x_n ...
1 votes
1 votes
1 answer
4
go_editor asked Mar 28, 2016
750 views
CAT 2000 | Question: 65
Let $x, y$ and $z$ be distinct integers, that are odd and positive. Which one of the following statements cannot be true? $xyz^2$ is odd. $(x − y)^2 z$ is even. $(x + y − z)^2 (x + y)$ is even. $(x − y) (y + z) (x + y − z)$ is odd
Let $x, y$ and $z$ be distinct integers, that are odd and positive. Which one of the following statements cannot be true?$xyz^2$ is odd.$(x − y)^2 z$ is even.$(x + y �...
0 votes
0 votes
1 answer
5
go_editor asked May 4, 2016
1,029 views
CAT 2003 | Question: 2-57
Let $x$ and $y$ be positive integers such that $x$ is prime and $y$ is composite. Then, $y – x$ cannot be an even integer $xy$ cannot be an even integer. $\frac{x+y}{x}$ cannot be an even integer None of these.
Let $x$ and $y$ be positive integers such that $x$ is prime and $y$ is composite. Then,$y – x$ cannot be an even integer$xy$ cannot be an even integer.$\frac{x+y}{x}$ c...
Link Copied!