in Quantitative Aptitude edited by
420 views
0 votes
0 votes

Answer the question based on the diagram

In the diagram below Angle $\text{ABC} = 90^{\circ} =  \text{Angle DCH = Angle DOE = Angle EHK = Angle FKL = Angle GLM = Angle LMN,}$

$\text{AB = BC = 2CH = 2CD = EH = FK = 2HK = 4KL = 2LM = MN}$

The magnitude of Angle $\text{FGO =}$

  1. $30^{\circ}$
  2. $45^{\circ}$
  3. $60^{\circ}$
  4. None of these
in Quantitative Aptitude edited by
13.4k points
420 views

Please log in or register to answer this question.

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true