0 votes 0 votes If $f(x) = \log(1+x)/(1-x))$, then $f(x)+f(y)=$ $f(x+y)$ $f(1+xy)$ $(x+y) \: f(1+xy)$ $f (\frac{x+y}{1+xy})$ Quantitative Aptitude cat2002 quantitative-aptitude functions + – go_editor asked Mar 2, 2016 • retagged Apr 9, 2022 by Lakshman Bhaiya go_editor 13.9k points 259 views answer comment Share See all 0 reply Please log in or register to add a comment.