in Quantitative Aptitude edited by
294 views
0 votes
0 votes

A vertical tower $\text{OP}$ stands at the centre $\text{O}$ of a square $\text{ABCD}.$ Let $h$ and $b$ denote the lengths $\text{OP}$ and $\text{AB}$ respectively. Suppose $\measuredangle \text{APB} = 60^{\circ}$. Then the relationship between $h$ and $b$ can be expressed as

  1. $2b^2 = h^2$
  2. $2h^2 = b^2$
  3. $3b^2 = 2h^2$
  4. $3h^2 = 2b^2$
in Quantitative Aptitude edited by
13.4k points
294 views

Please log in or register to answer this question.

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true