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There are two concentric circles such that the area of the outer circle is four times of the area of inner circle. Let A, B and C be the three distinct points on the perimeter of the outer circle such that AB and AC are tangents to the inner circle. If the area of the outer circle is $12$ square centimeters then the area of the triangle ABC (in square centimeter) would be

  1. $\pi \sqrt{12}$
  2. $\frac{9}{\pi}$
  3. $\frac{9 \sqrt{3} }{\pi}$
  4. $\frac{6 \sqrt{3} }{\pi}$
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