$a_{1}$= 81.33 $a_{2}$= –19

and $a_{ j }$ = $a_{ j-1 }$ - $a_{ j-2 }$ for j ≥ 3

$a_{3}$ = $a_{2}$ - $a_{1}$ = -19 - 81.33 = -100.33

Similarly,

$a_{4}$= $a_{3}$ - $a_{2}$ = -100.33 -(-19) = –81.33

$a_{5}$ = 19

$a_{6}$ = 100.33

$a_{7}$ = 81.33

$a_{8}$ = –19

Here we can clearly see that the sequence repeats itself after every 6 terms.

Sum of the first 6 terms of the sequence = 0

Thus, the sum of the first 6000 terms of this sequence = 0

The sum of the $6001^{st}$ and $6002^{nd}$ terms = 81.33 – 19 = 62.33

Hence,Option**(3)62.33** is the correct choice.