0 votes 0 votes The value of each of a set of silver coins varies as the square of its diameter if thickness remains constant, and it varies as the thickness if the diameter remains constant. If the diameters of two coins are in the ratio $4:3$ what should the ratio of their thicknesses be if the value of the first is $4$ times that of the second? $16:9$ $9:4$ $9:16$ $4:9$ Quantitative Aptitude cat1997 quantitative-aptitude ratio-proportion + – makhdoom ghaya asked May 31, 2017 makhdoom ghaya 8.0k points 2.7k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Let value be denoted by V, diameter by D, thickness by T V = $D^{2}T$ V1 = 16T1 V2 = 9T2 Here, V1 = 4*V2 => 16*T1 = 36*T2 T1/T2 = 36/16 = 9:4 (Option B) mudit23june answered Jun 28, 2017 mudit23june 346 points comment Share See all 0 reply Please log in or register to add a comment.