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The square of two digit number(ab) divided by half of itself resultant added by 18 then divided by 2
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The square of two digit number(ab) divided by half of itself resultant added by 18 then divided by 2 then we get reverse of original number(ba). how many combination of ab exist
(a) 9
(b) 8
(c) 7
(d) 6
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Feb 22
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malti007
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Mar 1
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Leen Sharma

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Best answer
$\frac{(ab)^{2}}{\frac{1}{2}* ab} =2* ab$
2*ab+18
$\frac{2*ab+18}{2}$
ab+9 =ba
baab=9
their are 8 possibilities
2112 =9
3223=9
4334=9
5445=9
6556=9
7667=9
8778=9
9889=9
answered
Mar 1
by
shivanisrivarshini
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1.7k
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