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12 24 60 140 290 ?
(a) 540
(b) 542
(c) 530
(d) 522
(e) 532
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$\\12 + 2^{2} +2^{3} = 24 \\24+3^{2}+3^{3}=60 \\60+4^{2}+4^{3}=140 \\140+5^{2}+5^{3}=290 \\290+6^{2}+6^{3}=542$

 

Hence,Option$(B)542 . $
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