1 votes 1 votes Let f(x,y)=xnym =P If x is doubled and y is halved, the new value of f is (A) 2n-m P (B) 2m-n P (C) 2(n-m) P (D) 2(m-n) P srestha asked Jun 6, 2016 srestha 5.2k points 1.3k views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 5 votes 5 votes f(x,y) = $x^{n} y^{m} = p$ x is doubled and y is havled f(2x,$\frac{y}{2}$) = $( 2x)^{n} (\frac{y}{2})^{m}$ = $2^{n} 2^{-m}x^{n}y^{m} =2^{n-m} P$ Hence, Option (A) $2^{n-m} P$ is the correct choice. Leen Sharma answered Jun 6, 2016 • selected Jun 6, 2016 by srestha Leen Sharma 11.5k points comment Share See all 0 reply Please log in or register to add a comment.